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4.905x^2-11x+2.5=0
a = 4.905; b = -11; c = +2.5;
Δ = b2-4ac
Δ = -112-4·4.905·2.5
Δ = 71.95
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{71.95}}{2*4.905}=\frac{11-\sqrt{71.95}}{9.81} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{71.95}}{2*4.905}=\frac{11+\sqrt{71.95}}{9.81} $
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